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n^2-75n-3000=0
a = 1; b = -75; c = -3000;
Δ = b2-4ac
Δ = -752-4·1·(-3000)
Δ = 17625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{17625}=\sqrt{25*705}=\sqrt{25}*\sqrt{705}=5\sqrt{705}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-5\sqrt{705}}{2*1}=\frac{75-5\sqrt{705}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+5\sqrt{705}}{2*1}=\frac{75+5\sqrt{705}}{2} $
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